打开题目:

计算1000次就可以拿到flag,显然就需要用Python写一个脚本:
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| import requests import re import time
url = "http://0fbb66bc-4f8d-4e64-8918-0697e7238950.node3.buuoj.cn/index.php" s = requests.session() source = s.get(url) view = source.text equation = eval("".join(re.findall("\<br\>\<br\>(.*?)\<br\>\<br\>\<form", view))) data = {'answer': equation} flag = s.post(url, data=data)
for i in range(1010): try: equation = eval("".join(re.findall("\<br\>\<br\>(\d.*?)\<br\>\<br\>\<form", flag.text))) flag = s.post(url, data={'answer': equation}) flag.encoding = 'utf-8' print(flag.text) time.sleep(0.5) except: Pass
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需要找个时间好好学习python的正则了。